15+2x-7=8(1/8x+2)

Solution for 15+2x-7=8(1/8x+2) equation:

15+2x-7=8(1/8x+2)

We move all terms to the left:

15+2x-7-(8(1/8x+2))=0


Domain of the equation: 8x+2))!=0

x∈R


We add all the numbers together, and all the variables

2x-(8(1/8x+2))+8=0

We multiply all the terms by the denominator


2x*8x+8*8x+2))-(8(1+2))=0

We add all the numbers together, and all the variables

2x*8x+8*8x+2))-(83)=0

We add all the numbers together, and all the variables

2x*8x+8*8x=0

Wy multiply elements

16x^2+64x=0

a = 16; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·16·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*16}=\frac{-128}{32}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*16}=\frac{0}{32}
=0
$