15+(3x-6)=(9+x)*2

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Solution for 15+(3x-6)=(9+x)*2 equation: 



15+(3x-6)=(9+x)*2

We move all terms to the left:

15+(3x-6)-((9+x)*2)=0

We add all the numbers together, and all the variables

(3x-6)-((x+9)*2)+15=0

We get rid of parentheses

3x-((x+9)*2)-6+15=0



We calculate terms in parentheses: -((x+9)*2), so:

(x+9)*2

We multiply parentheses

2x+18

Back to the equation:

-(2x+18)



We add all the numbers together, and all the variables

3x-(2x+18)+9=0

We get rid of parentheses

3x-2x-18+9=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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