15(z+4)-2(z-3)=5(z-1)+7(z-3)

Solution for 15(z+4)-2(z-3)=5(z-1)+7(z-3) equation:

15(z+4)-2(z-3)=5(z-1)+7(z-3)

We move all terms to the left:

15(z+4)-2(z-3)-(5(z-1)+7(z-3))=0

We multiply parentheses

15z-2z-(5(z-1)+7(z-3))+60+6=0


We calculate terms in parentheses: -(5(z-1)+7(z-3)), so:

5(z-1)+7(z-3)

We multiply parentheses

5z+7z-5-21

We add all the numbers together, and all the variables

12z-26

Back to the equation:

-(12z-26)


We add all the numbers together, and all the variables

13z-(12z-26)+66=0

We get rid of parentheses

13z-12z+26+66=0

We add all the numbers together, and all the variables

z+92=0

We move all terms containing z to the left, all other terms to the right

z=-92