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15(x-3)=3(2x-3)
We move all terms to the left:
15(x-3)-(3(2x-3))=0
We multiply parentheses
15x-(3(2x-3))-45=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
15x-6x+9-45=0
We add all the numbers together, and all the variables
9x-36=0
We move all terms containing x to the left, all other terms to the right
9x=36
x=36/9
x=4
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