15(x+4)-4(x-1)=6(x-2)+4(x-1)

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Solution for 15(x+4)-4(x-1)=6(x-2)+4(x-1) equation: 



15(x+4)-4(x-1)=6(x-2)+4(x-1)

We move all terms to the left:

15(x+4)-4(x-1)-(6(x-2)+4(x-1))=0

We multiply parentheses

15x-4x-(6(x-2)+4(x-1))+60+4=0



We calculate terms in parentheses: -(6(x-2)+4(x-1)), so:

6(x-2)+4(x-1)

We multiply parentheses

6x+4x-12-4

We add all the numbers together, and all the variables

10x-16

Back to the equation:

-(10x-16)



We add all the numbers together, and all the variables

11x-(10x-16)+64=0

We get rid of parentheses

11x-10x+16+64=0

We add all the numbers together, and all the variables

x+80=0

We move all terms containing x to the left, all other terms to the right

x=-80

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