15(t-5)+3t=6(3t+4)-10

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Solution for 15(t-5)+3t=6(3t+4)-10 equation: 



15(t-5)+3t=6(3t+4)-10

We move all terms to the left:

15(t-5)+3t-(6(3t+4)-10)=0

We add all the numbers together, and all the variables

3t+15(t-5)-(6(3t+4)-10)=0

We multiply parentheses

3t+15t-(6(3t+4)-10)-75=0



We calculate terms in parentheses: -(6(3t+4)-10), so:

6(3t+4)-10

We multiply parentheses

18t+24-10

We add all the numbers together, and all the variables

18t+14

Back to the equation:

-(18t+14)



We add all the numbers together, and all the variables

18t-(18t+14)-75=0

We get rid of parentheses

18t-18t-14-75=0

We add all the numbers together, and all the variables

-89!=0

There is no solution for this equation

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