15(b+2)-3b=4(3b+1)-7

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Solution for 15(b+2)-3b=4(3b+1)-7 equation: 



15(b+2)-3b=4(3b+1)-7

We move all terms to the left:

15(b+2)-3b-(4(3b+1)-7)=0

We add all the numbers together, and all the variables

-3b+15(b+2)-(4(3b+1)-7)=0

We multiply parentheses

-3b+15b-(4(3b+1)-7)+30=0



We calculate terms in parentheses: -(4(3b+1)-7), so:

4(3b+1)-7

We multiply parentheses

12b+4-7

We add all the numbers together, and all the variables

12b-3

Back to the equation:

-(12b-3)



We add all the numbers together, and all the variables

12b-(12b-3)+30=0

We get rid of parentheses

12b-12b+3+30=0

We add all the numbers together, and all the variables

33!=0

There is no solution for this equation

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