15(5c-9)=7c-3

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Solution for 15(5c-9)=7c-3 equation: 



15(5c-9)=7c-3

We move all terms to the left:

15(5c-9)-(7c-3)=0

We multiply parentheses

75c-(7c-3)-135=0

We get rid of parentheses

75c-7c+3-135=0

We add all the numbers together, and all the variables

68c-132=0

We move all terms containing c to the left, all other terms to the right

68c=132

c=132/68

c=1+16/17

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