15(4c-1)-12=58c+15

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Solution for 15(4c-1)-12=58c+15 equation: 



15(4c-1)-12=58c+15

We move all terms to the left:

15(4c-1)-12-(58c+15)=0

We multiply parentheses

60c-(58c+15)-15-12=0

We get rid of parentheses

60c-58c-15-15-12=0

We add all the numbers together, and all the variables

2c-42=0

We move all terms containing c to the left, all other terms to the right

2c=42

c=42/2

c=21

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