15(2x-6)+10=8(3x+20)

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Solution for 15(2x-6)+10=8(3x+20) equation: 



15(2x-6)+10=8(3x+20)

We move all terms to the left:

15(2x-6)+10-(8(3x+20))=0

We multiply parentheses

30x-(8(3x+20))-90+10=0



We calculate terms in parentheses: -(8(3x+20)), so:

8(3x+20)

We multiply parentheses

24x+160

Back to the equation:

-(24x+160)



We add all the numbers together, and all the variables

30x-(24x+160)-80=0

We get rid of parentheses

30x-24x-160-80=0

We add all the numbers together, and all the variables

6x-240=0

We move all terms containing x to the left, all other terms to the right

6x=240

x=240/6

x=40

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