14y2=21y

Solution for 14y2=21y equation:

14y^2=21y

We move all terms to the left:

14y^2-(21y)=0

a = 14; b = -21; c = 0;
Δ = b2-4ac
Δ = -212-4·14·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-21}{2*14}=\frac{0}{28}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+21}{2*14}=\frac{42}{28}
=1+1/2
$