14y+9+3y-12=3(4y-1)+5y

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Solution for 14y+9+3y-12=3(4y-1)+5y equation: 



14y+9+3y-12=3(4y-1)+5y

We move all terms to the left:

14y+9+3y-12-(3(4y-1)+5y)=0

We add all the numbers together, and all the variables

17y-(3(4y-1)+5y)-3=0



We calculate terms in parentheses: -(3(4y-1)+5y), so:

3(4y-1)+5y

We add all the numbers together, and all the variables

5y+3(4y-1)

We multiply parentheses

5y+12y-3

We add all the numbers together, and all the variables

17y-3

Back to the equation:

-(17y-3)



We get rid of parentheses

17y-17y+3-3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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