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14x^2=95
We move all terms to the left:
14x^2-(95)=0
a = 14; b = 0; c = -95;
Δ = b2-4ac
Δ = 02-4·14·(-95)
Δ = 5320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5320}=\sqrt{4*1330}=\sqrt{4}*\sqrt{1330}=2\sqrt{1330}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1330}}{2*14}=\frac{0-2\sqrt{1330}}{28} =-\frac{2\sqrt{1330}}{28} =-\frac{\sqrt{1330}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1330}}{2*14}=\frac{0+2\sqrt{1330}}{28} =\frac{2\sqrt{1330}}{28} =\frac{\sqrt{1330}}{14} $
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