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14x^2-29x-15=0
a = 14; b = -29; c = -15;
Δ = b2-4ac
Δ = -292-4·14·(-15)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-41}{2*14}=\frac{-12}{28} =-3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+41}{2*14}=\frac{70}{28} =2+1/2 $
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