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14x/196x=x
We move all terms to the left:
14x/196x-(x)=0
Domain of the equation: 196x!=0We add all the numbers together, and all the variables
x!=0/196
x!=0
x∈R
-1x+14x/196x=0
We multiply all the terms by the denominator
-1x*196x+14x=0
We add all the numbers together, and all the variables
14x-1x*196x=0
Wy multiply elements
-196x^2+14x=0
a = -196; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-196)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-196}=\frac{-28}{-392} =1/14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-196}=\frac{0}{-392} =0 $
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