14x-3x2=16

Solution for 14x-3x2=16 equation:

14x-3x^2=16

We move all terms to the left:

14x-3x^2-(16)=0

a = -3; b = 14; c = -16;
Δ = b2-4ac
Δ = 142-4·(-3)·(-16)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2}{2*-3}=\frac{-16}{-6}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2}{2*-3}=\frac{-12}{-6}
=+2
$