14x-3(4x+5)=-9+4(x-8)

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Solution for 14x-3(4x+5)=-9+4(x-8) equation: 



14x-3(4x+5)=-9+4(x-8)

We move all terms to the left:

14x-3(4x+5)-(-9+4(x-8))=0

We multiply parentheses

14x-12x-(-9+4(x-8))-15=0



We calculate terms in parentheses: -(-9+4(x-8)), so:

-9+4(x-8)

determiningTheFunctionDomain
4(x-8)-9

We multiply parentheses

4x-32-9

We add all the numbers together, and all the variables

4x-41

Back to the equation:

-(4x-41)



We add all the numbers together, and all the variables

2x-(4x-41)-15=0

We get rid of parentheses

2x-4x+41-15=0

We add all the numbers together, and all the variables

-2x+26=0

We move all terms containing x to the left, all other terms to the right

-2x=-26

x=-26/-2

x=+13

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