14x+7(x+1)=21(x+1)-14

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Solution for 14x+7(x+1)=21(x+1)-14 equation:


Simplifying
14x + 7(x + 1) = 21(x + 1) + -14

Reorder the terms:
14x + 7(1 + x) = 21(x + 1) + -14
14x + (1 * 7 + x * 7) = 21(x + 1) + -14
14x + (7 + 7x) = 21(x + 1) + -14

Reorder the terms:
7 + 14x + 7x = 21(x + 1) + -14

Combine like terms: 14x + 7x = 21x
7 + 21x = 21(x + 1) + -14

Reorder the terms:
7 + 21x = 21(1 + x) + -14
7 + 21x = (1 * 21 + x * 21) + -14
7 + 21x = (21 + 21x) + -14

Reorder the terms:
7 + 21x = 21 + -14 + 21x

Combine like terms: 21 + -14 = 7
7 + 21x = 7 + 21x

Add '-7' to each side of the equation.
7 + -7 + 21x = 7 + -7 + 21x

Combine like terms: 7 + -7 = 0
0 + 21x = 7 + -7 + 21x
21x = 7 + -7 + 21x

Combine like terms: 7 + -7 = 0
21x = 0 + 21x
21x = 21x

Add '-21x' to each side of the equation.
21x + -21x = 21x + -21x

Combine like terms: 21x + -21x = 0
0 = 21x + -21x

Combine like terms: 21x + -21x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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