14x(x+1)=0

Solution for 14x(x+1)=0 equation:

14x(x+1)=0

We multiply parentheses

14x^2+14x=0

a = 14; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·14·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*14}=\frac{-28}{28}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*14}=\frac{0}{28}
=0
$