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14x(7x-4)=60
We move all terms to the left:
14x(7x-4)-(60)=0
We multiply parentheses
98x^2-56x-60=0
a = 98; b = -56; c = -60;
Δ = b2-4ac
Δ = -562-4·98·(-60)
Δ = 26656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{26656}=\sqrt{784*34}=\sqrt{784}*\sqrt{34}=28\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-28\sqrt{34}}{2*98}=\frac{56-28\sqrt{34}}{196} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+28\sqrt{34}}{2*98}=\frac{56+28\sqrt{34}}{196} $
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