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14m^2-67m=63
We move all terms to the left:
14m^2-67m-(63)=0
a = 14; b = -67; c = -63;
Δ = b2-4ac
Δ = -672-4·14·(-63)
Δ = 8017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{8017}}{2*14}=\frac{67-\sqrt{8017}}{28} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{8017}}{2*14}=\frac{67+\sqrt{8017}}{28} $
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