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14m^2+31m+-10=0
We add all the numbers together, and all the variables
14m^2+31m=0
a = 14; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·14·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*14}=\frac{-62}{28} =-2+3/14 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*14}=\frac{0}{28} =0 $
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