14c-10c-2c+3c+c=12

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Solution for 14c-10c-2c+3c+c=12 equation: 



14c-10c-2c+3c+c=12

We move all terms to the left:

14c-10c-2c+3c+c-(12)=0

We add all the numbers together, and all the variables

6c-12=0

We move all terms containing c to the left, all other terms to the right

6c=12

c=12/6

c=2

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