14c+6=2(5+7c)-4

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Solution for 14c+6=2(5+7c)-4 equation: 



14c+6=2(5+7c)-4

We move all terms to the left:

14c+6-(2(5+7c)-4)=0

We add all the numbers together, and all the variables

14c-(2(7c+5)-4)+6=0



We calculate terms in parentheses: -(2(7c+5)-4), so:

2(7c+5)-4

We multiply parentheses

14c+10-4

We add all the numbers together, and all the variables

14c+6

Back to the equation:

-(14c+6)



We get rid of parentheses

14c-14c-6+6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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