14b(b-1)=-4+4b

Solution for 14b(b-1)=-4+4b equation:

14b(b-1)=-4+4b

We move all terms to the left:

14b(b-1)-(-4+4b)=0

We add all the numbers together, and all the variables

14b(b-1)-(4b-4)=0

We multiply parentheses

14b^2-14b-(4b-4)=0

We get rid of parentheses

14b^2-14b-4b+4=0

We add all the numbers together, and all the variables

14b^2-18b+4=0

a = 14; b = -18; c = +4;
Δ = b2-4ac
Δ = -182-4·14·4
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-10}{2*14}=\frac{8}{28}
=2/7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+10}{2*14}=\frac{28}{28}
=1
$