14a=2a(a-3)

Solution for 14a=2a(a-3) equation:

14a=2a(a-3)

We move all terms to the left:

14a-(2a(a-3))=0


We calculate terms in parentheses: -(2a(a-3)), so:

2a(a-3)

We multiply parentheses

2a^2-6a

Back to the equation:

-(2a^2-6a)


We get rid of parentheses

-2a^2+14a+6a=0

We add all the numbers together, and all the variables

-2a^2+20a=0

a = -2; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-2)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-2}=\frac{-40}{-4}
=+10
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-2}=\frac{0}{-4}
=0
$