14=3(u+2)+7u

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Solution for 14=3(u+2)+7u equation:



14=3(u+2)+7u
We move all terms to the left:
14-(3(u+2)+7u)=0
We calculate terms in parentheses: -(3(u+2)+7u), so:
3(u+2)+7u
We add all the numbers together, and all the variables
7u+3(u+2)
We multiply parentheses
7u+3u+6
We add all the numbers together, and all the variables
10u+6
Back to the equation:
-(10u+6)
We get rid of parentheses
-10u-6+14=0
We add all the numbers together, and all the variables
-10u+8=0
We move all terms containing u to the left, all other terms to the right
-10u=-8
u=-8/-10
u=4/5

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