14=2(3c+1)

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Solution for 14=2(3c+1) equation:



14=2(3c+1)
We move all terms to the left:
14-(2(3c+1))=0
We calculate terms in parentheses: -(2(3c+1)), so:
2(3c+1)
We multiply parentheses
6c+2
Back to the equation:
-(6c+2)
We get rid of parentheses
-6c-2+14=0
We add all the numbers together, and all the variables
-6c+12=0
We move all terms containing c to the left, all other terms to the right
-6c=-12
c=-12/-6
c=+2

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