14=16x2=43

Solution for 14=16x2=43 equation:

14=16x^2=43

We move all terms to the left:

14-(16x^2)=0

a = -16; b = 0; c = +14;
Δ = b2-4ac
Δ = 02-4·(-16)·14
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{14}}{2*-16}=\frac{0-8\sqrt{14}}{-32}
=-\frac{8\sqrt{14}}{-32}
=-\frac{\sqrt{14}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{14}}{2*-16}=\frac{0+8\sqrt{14}}{-32}
=\frac{8\sqrt{14}}{-32}
=\frac{\sqrt{14}}{-4}
$