147=10x-3+21x-5

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Solution for 147=10x-3+21x-5 equation: 



147=10x-3+21x-5

We move all terms to the left:

147-(10x-3+21x-5)=0

We add all the numbers together, and all the variables

-(31x-8)+147=0

We get rid of parentheses

-31x+8+147=0

We add all the numbers together, and all the variables

-31x+155=0

We move all terms containing x to the left, all other terms to the right

-31x=-155

x=-155/-31

x=+5

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