147-14(7-2t)=59-6(t-35)

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Solution for 147-14(7-2t)=59-6(t-35) equation: 



147-14(7-2t)=59-6(t-35)

We move all terms to the left:

147-14(7-2t)-(59-6(t-35))=0

We add all the numbers together, and all the variables

-14(-2t+7)-(59-6(t-35))+147=0

We multiply parentheses

28t-(59-6(t-35))-98+147=0



We calculate terms in parentheses: -(59-6(t-35)), so:

59-6(t-35)

determiningTheFunctionDomain
-6(t-35)+59

We multiply parentheses

-6t+210+59

We add all the numbers together, and all the variables

-6t+269

Back to the equation:

-(-6t+269)



We add all the numbers together, and all the variables

28t-(-6t+269)+49=0

We get rid of parentheses

28t+6t-269+49=0

We add all the numbers together, and all the variables

34t-220=0

We move all terms containing t to the left, all other terms to the right

34t=220

t=220/34

t=6+8/17

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