146=(4y-8)+(5y+3)

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Solution for 146=(4y-8)+(5y+3) equation: 



146=(4y-8)+(5y+3)

We move all terms to the left:

146-((4y-8)+(5y+3))=0



We calculate terms in parentheses: -((4y-8)+(5y+3)), so:

(4y-8)+(5y+3)

We get rid of parentheses

4y+5y-8+3

We add all the numbers together, and all the variables

9y-5

Back to the equation:

-(9y-5)



We get rid of parentheses

-9y+5+146=0

We add all the numbers together, and all the variables

-9y+151=0

We move all terms containing y to the left, all other terms to the right

-9y=-151

y=-151/-9

y=16+7/9

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