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144=x2+25x
We move all terms to the left:
144-(x2+25x)=0
We add all the numbers together, and all the variables
-(+x^2+25x)+144=0
We get rid of parentheses
-x^2-25x+144=0
We add all the numbers together, and all the variables
-1x^2-25x+144=0
a = -1; b = -25; c = +144;
Δ = b2-4ac
Δ = -252-4·(-1)·144
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{1201}}{2*-1}=\frac{25-\sqrt{1201}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{1201}}{2*-1}=\frac{25+\sqrt{1201}}{-2} $
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