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144=x(x-50)
We move all terms to the left:
144-(x(x-50))=0
We calculate terms in parentheses: -(x(x-50)), so:We get rid of parentheses
x(x-50)
We multiply parentheses
x^2-50x
Back to the equation:
-(x^2-50x)
-x^2+50x+144=0
We add all the numbers together, and all the variables
-1x^2+50x+144=0
a = -1; b = 50; c = +144;
Δ = b2-4ac
Δ = 502-4·(-1)·144
Δ = 3076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3076}=\sqrt{4*769}=\sqrt{4}*\sqrt{769}=2\sqrt{769}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{769}}{2*-1}=\frac{-50-2\sqrt{769}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{769}}{2*-1}=\frac{-50+2\sqrt{769}}{-2} $
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