144=(x+10)(x+8)

Solution for 144=(x+10)(x+8) equation:

144=(x+10)(x+8)

We move all terms to the left:

144-((x+10)(x+8))=0

We multiply parentheses ..

-((+x^2+8x+10x+80))+144=0


We calculate terms in parentheses: -((+x^2+8x+10x+80)), so:

(+x^2+8x+10x+80)

We get rid of parentheses

x^2+8x+10x+80

We add all the numbers together, and all the variables

x^2+18x+80

Back to the equation:

-(x^2+18x+80)


We get rid of parentheses

-x^2-18x-80+144=0

We add all the numbers together, and all the variables

-1x^2-18x+64=0

a = -1; b = -18; c = +64;
Δ = b2-4ac
Δ = -182-4·(-1)·64
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{145}}{2*-1}=\frac{18-2\sqrt{145}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{145}}{2*-1}=\frac{18+2\sqrt{145}}{-2}
$