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142/5x+6.55=(-11)*1/8x-2.45+17x
We move all terms to the left:
142/5x+6.55-((-11)*1/8x-2.45+17x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 8x-2.45+17x)!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
8x+17x)!=2.45
x∈R
(1136x+17x)-2.45)/(40x^2+17x)-2.45)+(-((-11)*1*5x)/(40x^2+17x)-2.45)+6.55=0
We add all the numbers together, and all the variables
(+1153x)-2.45)/(40x^2+17x)-2.45)+(-((-11)*1*5x)/(40x^2+17x)-2.45)+6.55=0
We get rid of parentheses
1153x-2.45)/(40x^2+17x)-2.45)+(-((-11)*1*5x)/(40x^2+17x)-2.45)+6.55=0
We multiply all the terms by the denominator
1153x*(40x^2-2.45)+17x)-2.45)+(-((-11)*1*5x)+17x-2.45)+6.55)*(40x^2=0
We multiply parentheses
46120x^3-2824.85x+17x)-2.45)+(-((-11)*1*5x)+17x-2.45)+6.55)*(40x^2=0
We do not support expression: x^3
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