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14/3x+2x-5=15
We move all terms to the left:
14/3x+2x-5-(15)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2x+14/3x-20=0
We multiply all the terms by the denominator
2x*3x-20*3x+14=0
Wy multiply elements
6x^2-60x+14=0
a = 6; b = -60; c = +14;
Δ = b2-4ac
Δ = -602-4·6·14
Δ = 3264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3264}=\sqrt{64*51}=\sqrt{64}*\sqrt{51}=8\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-8\sqrt{51}}{2*6}=\frac{60-8\sqrt{51}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+8\sqrt{51}}{2*6}=\frac{60+8\sqrt{51}}{12} $
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