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14-8x=5x(x-1)
We move all terms to the left:
14-8x-(5x(x-1))=0
We calculate terms in parentheses: -(5x(x-1)), so:We get rid of parentheses
5x(x-1)
We multiply parentheses
5x^2-5x
Back to the equation:
-(5x^2-5x)
-5x^2-8x+5x+14=0
We add all the numbers together, and all the variables
-5x^2-3x+14=0
a = -5; b = -3; c = +14;
Δ = b2-4ac
Δ = -32-4·(-5)·14
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-17}{2*-5}=\frac{-14}{-10} =1+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+17}{2*-5}=\frac{20}{-10} =-2 $
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