If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5-(b/3) = 2
(x^3-3)/(x^3+3)
2*x
sin((pi*x)/25)*(4*cos((14*pi*t)/25)-(11*cos((16*pi*t)/25))) = 0
7*e^x-(22*ctg(x))+9*x-1
| 35a+21= | | -22=400-6 | | 3-(5x-6)=-8x+3 | | 5-b/3=2 | | 7(x-3)-3=3x+18 | | 7-7a+12=-8a+14 | | ln(x+1)+ln(x+2)=ln(18) | | 16y^4-y^2-12=0 | | r-6=3 | | ln(x+1.32)=0.69960 | | m=11+-8 | | ln(x+1.32)=0.81 | | s=-9+4 | | (1/6)x(1/5) | | 75-5[4(n-3)]= | | 2x+3y-4x-y= | | 16x=-12x | | 22-(x-7)=6x-6 | | y=50a+25b | | 5x/6+x/8=3/4 | | 6z-6w=c-1 | | (12×1/3)-2=5-(9×1/3) | | r-8.1=-7.8 | | 15(2x-4)=13(2x+5) | | x/4+2/3=x/3 | | 4(x-2)=4+2(x-3) | | 9x+10=6x-500 | | y=3.5x-2.4 | | y=3.4x+4.8 | | y=-2.3x-1.7 | | 5(2x-1)=3+2(3x+4) | | 7m(2-m)-[3m(8+m)-m]= |