14-2(3p=1)=6(4+p)

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Solution for 14-2(3p=1)=6(4+p) equation: 



14-2(3p=1)=6(4+p)

We move all terms to the left:

14-2(3p-(1))=0

We multiply parentheses

-6p+2+14=0

We add all the numbers together, and all the variables

-6p+16=0

We move all terms containing p to the left, all other terms to the right

-6p=-16

p=-16/-6

p=2+2/3

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