14-2(3p+1)=64+p

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Solution for 14-2(3p+1)=64+p equation: 



14-2(3p+1)=64+p

We move all terms to the left:

14-2(3p+1)-(64+p)=0

We add all the numbers together, and all the variables

-2(3p+1)-(p+64)+14=0

We multiply parentheses

-6p-(p+64)-2+14=0

We get rid of parentheses

-6p-p-64-2+14=0

We add all the numbers together, and all the variables

-7p-52=0

We move all terms containing p to the left, all other terms to the right

-7p=52

p=52/-7

p=-7+3/7

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