14-2(3p+1)=6(6+p)

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Solution for 14-2(3p+1)=6(6+p) equation: 



14-2(3p+1)=6(6+p)

We move all terms to the left:

14-2(3p+1)-(6(6+p))=0

We add all the numbers together, and all the variables

-2(3p+1)-(6(p+6))+14=0

We multiply parentheses

-6p-(6(p+6))-2+14=0



We calculate terms in parentheses: -(6(p+6)), so:

6(p+6)

We multiply parentheses

6p+36

Back to the equation:

-(6p+36)



We add all the numbers together, and all the variables

-6p-(6p+36)+12=0

We get rid of parentheses

-6p-6p-36+12=0

We add all the numbers together, and all the variables

-12p-24=0

We move all terms containing p to the left, all other terms to the right

-12p=24

p=24/-12

p=-2

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