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14-(x+5)=3(x+9)-12
We move all terms to the left:
14-(x+5)-(3(x+9)-12)=0
We get rid of parentheses
-x-(3(x+9)-12)-5+14=0
We calculate terms in parentheses: -(3(x+9)-12), so:We add all the numbers together, and all the variables
3(x+9)-12
We multiply parentheses
3x+27-12
We add all the numbers together, and all the variables
3x+15
Back to the equation:
-(3x+15)
-1x-(3x+15)+9=0
We get rid of parentheses
-1x-3x-15+9=0
We add all the numbers together, and all the variables
-4x-6=0
We move all terms containing x to the left, all other terms to the right
-4x=6
x=6/-4
x=-1+1/2
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