14-(n-4)=6(n+2)

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Solution for 14-(n-4)=6(n+2) equation:



14-(n-4)=6(n+2)
We move all terms to the left:
14-(n-4)-(6(n+2))=0
We get rid of parentheses
-n-(6(n+2))+4+14=0
We calculate terms in parentheses: -(6(n+2)), so:
6(n+2)
We multiply parentheses
6n+12
Back to the equation:
-(6n+12)
We add all the numbers together, and all the variables
-1n-(6n+12)+18=0
We get rid of parentheses
-1n-6n-12+18=0
We add all the numbers together, and all the variables
-7n+6=0
We move all terms containing n to the left, all other terms to the right
-7n=-6
n=-6/-7
n=6/7

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