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14-(5x-6)=-6x(x+1)
We move all terms to the left:
14-(5x-6)-(-6x(x+1))=0
We get rid of parentheses
-5x-(-6x(x+1))+6+14=0
We calculate terms in parentheses: -(-6x(x+1)), so:We add all the numbers together, and all the variables
-6x(x+1)
We multiply parentheses
-6x^2-6x
Back to the equation:
-(-6x^2-6x)
-(-6x^2-6x)-5x+20=0
We get rid of parentheses
6x^2+6x-5x+20=0
We add all the numbers together, and all the variables
6x^2+x+20=0
a = 6; b = 1; c = +20;
Δ = b2-4ac
Δ = 12-4·6·20
Δ = -479
Delta is less than zero, so there is no solution for the equation
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