14+5/7x-20=40(1/7x-1)

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Solution for 14+5/7x-20=40(1/7x-1) equation: 



14+5/7x-20=40(1/7x-1)

We move all terms to the left:

14+5/7x-20-(40(1/7x-1))=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R





Domain of the equation: 7x-1))!=0

x∈R



We add all the numbers together, and all the variables

5/7x-(40(1/7x-1))-6=0

We calculate fractions


35x/49x^2+(-(40(1*7x)/49x^2-6=0

We add all the numbers together, and all the variables

35x/49x^2+(-(40(+1*7x)/49x^2-6=0

We calculate fractions

We do not support expression: x^4

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