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14+4(2x-1)=5(x+2)
We move all terms to the left:
14+4(2x-1)-(5(x+2))=0
We multiply parentheses
8x-(5(x+2))-4+14=0
We calculate terms in parentheses: -(5(x+2)), so:We add all the numbers together, and all the variables
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
8x-(5x+10)+10=0
We get rid of parentheses
8x-5x-10+10=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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