14+1/5(j+10)=2/5(25+j)

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Solution for 14+1/5(j+10)=2/5(25+j) equation: 



14+1/5(j+10)=2/5(25+j)

We move all terms to the left:

14+1/5(j+10)-(2/5(25+j))=0



Domain of the equation: 5(j+10)!=0

j∈R





Domain of the equation: 5(25+j))!=0

j∈R



We add all the numbers together, and all the variables

1/5(j+10)-(2/5(j+25))+14=0

We calculate fractions


(5jj/(5(j+10)*5(j+25)))+(-10jj/(5(j+10)*5(j+25)))+14=0



We calculate terms in parentheses: +(5jj/(5(j+10)*5(j+25))), so:

5jj/(5(j+10)*5(j+25))

We multiply all the terms by the denominator


5jj

Back to the equation:

+(5jj)





We calculate terms in parentheses: +(-10jj/(5(j+10)*5(j+25))), so:

-10jj/(5(j+10)*5(j+25))

We multiply all the terms by the denominator


-10jj

Back to the equation:

+(-10jj)



We get rid of parentheses

5jj-10jj+14=0

We move all terms containing j to the left, all other terms to the right

5jj-10jj=-14

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