14+(5/7)x=(4/7)x-4

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Solution for 14+(5/7)x=(4/7)x-4 equation: 



14+(5/7)x=(4/7)x-4

We move all terms to the left:

14+(5/7)x-((4/7)x-4)=0



Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 7)x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+5/7)x-((+4/7)x-4)+14=0

We multiply parentheses

5x^2-((+4/7)x-4)+14=0

We multiply all the terms by the denominator


5x^2*7)x-4)-((+14*7)x-4)+4=0

We add all the numbers together, and all the variables

5x^2*7)x-4)-(98x-4)+4=0

Wy multiply elements

35x^3=0

We do not support expression: x^3

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