14(x+1)/6=3(x+4)/9

Solution for 14(x+1)/6=3(x+4)/9 equation:

14(x+1)/6=3(x+4)/9

We move all terms to the left:

14(x+1)/6-(3(x+4)/9)=0

We calculate fractions


14x/()+(-(3(x+4)*6)/()=0


We calculate terms in parentheses: +(-(3(x+4)*6)/(), so:

-(3(x+4)*6)/(

We multiply all the terms by the denominator


-(3(x+4)*6)


We calculate terms in parentheses: -(3(x+4)*6), so:

3(x+4)*6

We multiply parentheses

18x+72

Back to the equation:

-(18x+72)


We get rid of parentheses

-18x-72

Back to the equation:

+(-18x-72)


We get rid of parentheses

14x/()-18x-72=0

We multiply all the terms by the denominator


14x-18x*()-72*()=0

We add all the numbers together, and all the variables

14x-18x*()=0